how to run job depending on other any job success?

I need to run current job based on previous jobs.Which means if I have 2jobs before current job , I need to run current job if any one job is triggered/success. I tried needs event by putting 2 jobs inside.but it is running current job only if 2 jobs got success. Basically I’m expecting or functionality. Any solution?

[fhammerl]

Try this example workflow. You can use always() to trigger a job regardless of other jobs failing. Then, in your job that has dependencies, you can set its run condition to if: ${{ always() && contains(join(needs.*.result, ','), 'success') }}.

name: Run job if any dependency succeeds
on:
  push:
    branches: [ main ]
jobs:
  dep1:
    runs-on: ubuntu-latest
    steps:
      - name: Run FAILING script
        run: exit 1 
  dep2:
    runs-on: ubuntu-latest
    steps:
      - name: Run SUCCESS script
        run: echo Success
  job:
    runs-on: ubuntu-latest
    if: ${{ always() && contains(join(needs.*.result, ','), 'success') }}
    needs: [dep1, dep2]
    steps:
      - name: Hello World        
        env:
          NEEDS: ${{ toJSON(needs) }}     
        run: |
          echo "$NEEDS"
  nextjob:
    runs-on: ubuntu-latest
    if: ${{ always() }}
    needs: [job]
    steps:
      - name: Hello World        
        env:
          NEEDS: ${{ toJSON(needs) }}     
        run: |
          echo "$NEEDS"

Please note that if you ever add continue-on-error: true to the failing job dep1, it will set its result to success, so needs.dep1.result will always be success, thus rendering the check in job useless.

[PavelYatskevich]

Saved my day!