Conditional expression in Arrow function

The no-confusing-arrow rule is enabled, so the following syntax is an error: const fn = a => a ? 1 : 2;

The arrow-body-style rule is enabled, so the following syntax is an error too: const fn = a => { return a ? 1 : 2; };

So the only way to write it following the rules is the following one: const fn = a => { if (a) return 2; return 3; };

Is this correct? Or is there another way to write the same stuff in a different way?

[tough-griff]

The allowParens option is set to true, so

const fn = a => (a ? 1 : 2);

should not cause a linter error.

[TejalGujar]

Got it

On Sun 19 Jul, 2020, 1:14 AM Jordan Harband, [e-mail] wrote:

@tejalbadgujar https://github.com/tejalbadgujar if your function doesn’t use this or arguments or super, and isn’t newed, then there’s really no difference. All three of those functions could be arrows or normal ones, just the same.

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