NOT sort by score option

The find method always sorts by .score. What I need is that it doesn’t sort at all but leaves the order of the original list.

So, looking at the Basic usage that example returns:

Output: lisp, kotlin, elixir

but what I need it to be is:

Output: kotlin, elixir, lisp

because that’s the order they appear in the list option:

const list = ['go', 'javascript', 'python', 'rust', 
              'swift', 'kotlin', 'elixir', 'java', 
              'lisp', 'v', 'zig', 'nim', 'rescript', 
              'd', 'haskell']

The reason for needing this is that my list that I search on are sorted by “popularity”. If the user only type something really short like f I really want to favor the popular items first because the assumed likelihood that it’s what the user expects to find.

So ideal would be something like:

const entries = fzf.find('li', {sort: (item) => item})

or

const entries = fzf.find('li', {sortByScore: false})

so that it only “filters” the list.

[ajitid]

Okay, I’ll close it for now then.

[ajitid]

I’m already working on a branch https://github.com/ajitid/fzf-for-js/tree/feat/skip-score-sorting that will add a boolean sort.