TypeScript typings of `EqualityFn`

The arguments of EqualityFn are defined as being unknown even though they are known (i.e. the same as …newArgs of ResultFn).

Our build did fail today due to the recently added TypeScript types. My suggestion would be to type the args of EqualityFn as any (just like the typings on DefinitelyTyped did which does make that users do not have to cast the unknown type) or to strong-type it, e.g.:

 export type EqualityFn<Args = any> = (
  newArgs: Args,
  lastArgs: Args,
) => boolean;

export default function memoizeOne<
  ResultFn extends (this: any, ...newArgs: T) => ReturnType<ResultFn>, 
  T extends any[]
>(resultFn: ResultFn, isEqual: EqualityFn<T> = areInputsEqual): ResultFn {
...

[alexreardon]

Fixed in 5.1.1

[alexreardon]

I think this should be fine then:

type EqualityFn = (newArgs: any[], lastArgs: any[]) => boolean;

it is fairly loose, but i don’t think the friction is worth typing it stricter for now