Trying to download to path

I’m trying to use a library like Fetch (https://github.com/tonyofrancis/Fetch) to download: photos, videos, audios and documents to the filesystem. What is the correct way to generate a path for simple storage to download to?

findViewById<FloatingActionButton>(R.id.fab).setOnClickListener {
            val tsLong = System.currentTimeMillis() / 1000
            val ts = tsLong.toString()
            val url = "https://unsplash.com/photos/FQq88kJLoyI/download?force=true"
            val mediaFile = MediaStoreCompat.createImage(this, FileDescription("image${ts}.jpg", subFolder = "Bramti Images", mimeType = "image/jpg"), ImageMediaDirectory.PICTURES)
//           val intent = Intent(applicationContext, DownloadService::class.java)
//            intent.putExtra("downloadUrl", url)
              val path = mediaFile!!.absolutePath
//            intent.putExtra("saveFilePath", path)

            enqueueDownload(url, path)
        }
 }

    private fun enqueueDownload(url: String, filePath: String) {
        request = Request(url, filePath)
        fetch.attachFetchObserversForDownload(request.id, this)
                .enqueue(request, { result -> request = result }, { result -> Log.d("MainActivity", "SingleDownloadActivity Error: %1${result}s") })
    }

[anggrayudi]

DocumentFileCompat.from...() returns null if you have no URI access. You had better cloning this project and test the code on your own. I will close this issue since the discussion becoming more complex and I have no much time to teach you.

I’ll write the documentation, but not for now since this library is still in big development.

[DavidKmn]

What if I just wanted to create a file in the Environment.DIRECTORY_DOCUMENTS and then write to its uri. I tried (after giving access) this:

DocumentFileCompat.fromPublicFolder(this, PublicDirectory.DOWNLOADS, subFile = "doc${ts}.pdf", requiresWriteAccess = true)

however this returns null (it does not return null if I omit the subFile parameter, but then I am unclear on how and where to name the file)