While loops make the browser freeze

I’m trying to get the response of an api request made with ajax.ajax() and the response is stored into [‘apiResponse’] in the HTML5 Local Storage (but the rest of the python function processes without waiting for it be put into localStorage).

Because of this I need to wait for it before getting the response and I thought I could do what I did below for the program to wait before it proceed.

Unfortunately the browser seems to freeze every time I put a while loop…

If someone know how to make Brython and the browser to stop freezing or another method to do what I wanna do…

(It would really help me as it’s the only step before succeeding getting Spotify api requests response)

from browser import ajax #to make requests
from browser.local_storage import storage as localStorage #to access HTML5 Local Storage

import json #to convert a json-like string into a Python Dict

#Request to the API
def on_complete(req):
    if req.status==200 or req.status==0:
        localStorage['apiResponse'] = req.text
    else:
        print("An error occured while asking Spotify for data")

def apiRequest(requestUrl, requestMethod):
    req = ajax.ajax()
    req.bind('complete', on_complete)
    req.open(requestMethod, requestUrl, True)
    req.set_header('Authorization', localStorage['header'])
    req.send()

def response():
    while localStorage['apiResponse'] == '':
        continue
    print('done')
    return json.loads(localStorage['apiResponse'])

Thanks in advance!

[PierreQuentel]

I understand that it’s how you would like the program to run, but I’m afraid it’s not possible. Sending an Ajax request doesn’t block the program until the request completes and then executes the next instruction - unless the API supports blocking Ajax calls, ie with the third parameter of req.open() set to False, but I would be surprised if it works.

[Animenosekai]

Great ! can we close the issue then ?

@PierreQuentel Yes!

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