Leading Double 00 in Country Code

libphonenumber-js: v 1.0.24
node v7.10.1

I don’t get the same result/format a number to E.164 for +49 and 0049?

libphonenumber.parse( '0049(89) 11196611' ) //returns {}
libphonenumber.parse( '0049(89) 11196611' , 'DE') //returns {}
new libphonenumber.AsYouType('DE').input('0049(89) 11196611') //'00498912196611'

libphonenumber.parse( '0049(89) 11196611' ) //returns {}
libphonenumber.parse( '0049(89) 11196611' , 'DE') //returns {}
new libphonenumber.AsYouType('DE').input('0049(89) 11196611') //'00498912196611'

The same number libphonenumber.appspot.com Is correctly trnaformed to E.164

Is there are reason why a leading 00 is not equal to a +? Or can it be safely tranformed:

let tel =  '0049(89) 11196611'.replace(/^00/, '+')
let parsedNumber = libphonenumber.parse(tel)
if (parsedNumber.phone)
  libphonenumber.format(parsedNumber.phone,  parsedNumber.country, 'E.164')

[catamphetamine]

Interestingly, this one turned out to be quite simple. Released libphonenumber-js@1.7.44. Closing.

[catamphetamine]

@360disrupt Let’s start with your case. You seem to have reported it a long time ago, and the issue seems to have been fixed since then:

Demo result:

Google’s demo result

So I guess parsePhoneNumberFromString() works.

About AsYouType then. It doesn’t seem to work:

I’ll see if that could be fixed.

Now, @dcustodio 's case. Provide an exact case when the library’s parsePhoneNumberFromString result differs from Google’s demo result. P.S.: for searching multiple numbers in text use findPhoneNumbersInText() function.