Array of objects with some of them literals

How are you? I’m thinking about the following validation with zod and I have no clue on how to do it (or if it’s possible with zod). I want an array of objects, all with the same shape of course with some of them with literal props, I need these always present in the array.

Example: I need always in the array the objects those with name required1 and required2, and then other objects optionals following the same shape.

[
    {
      name: z.literal('required1'),
      otherprop: z.number()
    },
    {
      name: z.literal('required2'),
      otherprop: z.number()
    },
    // I want to include one or more of the following too.
    {
      name: z.string(),
      otherprop: z.number()
    },
]

This other example will throw because required2 is missing

[
    {
      name: z.literal('required1'),
      otherprop: z.number()
    },
    // I want to include one or more of the following too.
    {
      name: z.string(),
      otherprop: z.number()
    },
]

Any clue?

Thanks.

[scotttrinh]

I’m going to close this, but feel free to post your solution here when you’re done if you come up with something that you like!

[Lzok]

I solved it doing the following (simplified here)

const elementSchema = z.object({
  name: z.string(),
  otherprop: z.number(),
})
type Element = z.infer<typeof elementSchema>;

function refineNames(elements: Element[]): boolean {
	// In my real code, here I have a function that returns the array of required names for the case.
       const names = ['required1', 'required2'];

       return names.every((el: string) => elements.some(x => x.name === el));
}

function hasDuplicates(elements: Element[]): boolean {
	const names = elements.map(e => e.name);

	return names.length !== new Set(names).size;
}

z.array(elementSchema).superRefine((elements, ctx) => {
		if (refineNames(elements)) {
			ctx.addIssue({
				code: z.ZodIssueCode.custom,
				message: `There are missing names. Required names are ${names.join(', ')}`,
			});
		}

		if (hasDuplicates(elements)) {
			ctx.addIssue({
				code: z.ZodIssueCode.custom,
				message: 'No duplicated name allowed.',
			});
		}
	}),

Thanks!