Using .mock() as a .default() only in testing?

Hey hey,

So we are looking at using a “zod first approach” to developing libraries (DDD?).

As such we have just been looking at a way to quickly mock inputs during develop and testing. One idea we had was to use .default() to produce the test data - but then we realised this didn’t make sense as we would then have these defaults in production as well.

It would be great if there were an equivalent .mock() that would return a mock value if no other is received and node env == dev or test (or some other config).

cc @iainkirkpatrick

[colinhacks]

The ability to passing a “dynamic default” function into .default is now available in zod@2.0.0-beta.16 👍

const randomDefault = z
    .number()
    .default(() => Math.random())

// returns a new random number every time `parse` is called
randomDefault.parse(undefined);

Zod makes sure the returned value matches the expected type signature:

const randomDefault = z
    .number()
    .default(() => 'qwerty') // TypeError

[colinhacks]

I just opened an RFC for mocking here: https://github.com/vriad/zod/issues/197

Feel free to comment 🤙