Add a way of running async code in debug console
See original GitHub issueWhen running Future returning code in the debug console, only a
_Future (Instance of ‘Future<void>’)
instance is returned. And no way of interacting with it.
It doesn’t even works the .then((s){print('funcó: $s');})
call
Issue Analytics
- State:
- Created 4 years ago
- Reactions:1
- Comments:7 (4 by maintainers)
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Top GitHub Comments
I’ve opened https://github.com/dart-lang/sdk/issues/40198 as a request to collect 👍 's on, thanks!
I get this, when I click “Evaluate in Debug Console”:
Just adding this phrase, so that it can be found more easily. I had a hard time finding this issue.