How can i run my task between some time?

It seems that the package has not function to execute a task from time to time.

Is there any pythonic method to achieve it?

Like…

import schedule

def task():
    print 'Hello'

schedule.every(5).minutes.between('12:00','24:00').do(task)

[ChuanPoLee]

Hi, @ciroanacleto Although I never use .tag(), but it sounds interesting. It can function like a switch. Here is another example, if you don’t need job to run at exactly every o’clock, try this:

def job():
    print("I'm working %s"%(datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S')))
def control_job():
    #run between Mon. to Fri. and 09 ~ 18 hour/day
    tnow = datetime.datetime.now()
    hh = tnow.strftime('%H')   #hour like '09'
    wk = tnow.isoweekday() #Mon =1
    if (('08'<hh<'18') and (1 <=wk <=5)):
        job()
    
schedule.every().hour.do(control_job)

[ChuanPoLee]

ok, I found some way to do this.

import schedule
import time, datetime

def job():
    print("I'm working %s"%(datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S')))

def control_job():
    tnow = datetime.datetime.now()
    hm = tnow.strftime('%H:%M')   #hour:minute like '10:00'
    if hm in run_hour:
        if run_hour[hm] == 0:
            #run job and set the run flag to 1
            job()
            run_hour[hm]=1
            #debug
            print(run_hour)
    #time < 10:00 and time> 22:00 reset all flag to 0
    if ((hm <'10:00') or (hm >'22:01')):
        for i in run_hour:
            run_hour[i]=0
    
#global variable, set every hour as a run flag
run_hour = {'10:00':0, '11:00':0, '12:00':0, '13:00':0, '14:00':0, '15:00':0, 
'16:00':0, '17:00':0, '18:00':0, '19:00':0, '20:00':0, '21:00':0, '22:00':0 }

schedule.every(59).seconds.do(control_job)  #set less than 1 min. ensure compare the flag at least once per minute.
while True:
    schedule.run_pending()
    time.sleep(1)