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# Matrix.display() does not work for default value

See original GitHub issue

I wrote the following code to run an example for Matrix.display()

``````from raytracing import *
M= Matrix(A=1,B=3,C=1,D=4)
M.display()
``````

It does not display anything and it does not rais any error. when I add other inputs of the matrix It works properly.

``````from raytracing import *

M1= Matrix(A=1,B=3,C=-1/3,D=1,physicalLength=3,frontVertex=4,
backVertex=2,frontIndex=1,backIndex=1,apertureDiameter=6,
label='Lens')
M1.display()
``````

I suggest to add some errors or change the default value so it works!

### Issue Analytics

• State:
• Created 3 years ago
• Comments:7 (7 by maintainers)

#### Top GitHub Comments

1reaction
dccotecommented, May 22, 2020

Good point: front and back vertices really represent actual physical interfaces, so it is possible to not have any (Space(d=10) is an example of such matrix). Constructing a matrix manually is possible, but it needs to fill certain requirements: the determinant must be at least n1/n2 (or the inverse, I don’t remember), and if C != 0, then vertices must be defined for sure because C is the power (-1/f) and therefore there must be vertices. If these conditions are not filled, we should raise an ValueError()

0reactions
JLBegincommented, Jun 16, 2020

N.B.: The code for Matrix.display() is now under raytracing.figure.MatrixGraphic.display()

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