IgResponseError: POST /api/v1/direct_v2/threads/broadcast/link/ - 403 Forbidden;

Bug Report

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Notes

Your issue will be closed if you violate any rule below.

• You need to include a meaningful section of your code (not your entire project and not a single line).
• Please do not add screenshots as they’re not easy to work with.
• Errors like IgActionSpamError (feedback_required), IgCheckpointError (challenge_required), checkpont_required, login_required are “common” and there are multiple issues, search here.
• You can delete this section after reading it.

Form

Put an [x] if you meet the condition, else leave [ ].

Requirements

• I’ve searched the Issues
• I’ve read the basic concepts
• I’m using the latest version
• I’ve debugged my code using the DEBUG variable.

Platform

• I’m using Node.js version YOUR_VERSION (node -v)
• I’m using electron
• I’m using the browser YOUR_BROWSER_AND_VERSION
• I’m using some other environment YOUR_ENV

Description

A specific description of your bug, so it’s understandable to anyone. If you have pictures or videos to upload, please add a link like this: [title](url).

YOUR DESCRIPTION HERE

Code

Add a meaningful section of your code here. If you are using TypeScript replace js with typescript.

/* tslint:disable:no-console */
import { DirectThreadEntity, IgApiClient } from '../src';

const ig = new IgApiClient();

async function login() {
  // basic login-procedure
  ig.state.generateDevice(process.env.IG_USERNAME);
  ig.state.proxyUrl = process.env.IG_PROXY;
  await ig.account.login(process.env.IG_USERNAME, process.env.IG_PASSWORD);
}

async function sendMessageLink(thread: DirectThreadEntity, message: string, links: string[]) {
  return await thread.broadcastLink(message, links);
}

(async () => {
  await login();

  const thread = ig.entity.directThread(process.env.IG_THREAD_ID);

  await sendMessageLink(thread, process.env.IG_MESSAGE, [process.env.IG_MESSAGE_LINK]);
})();

Error and Output

/Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/src/core/request.js:126 return new errors_1.IgResponseError(response); ^

IgResponseError: POST /api/v1/direct_v2/threads/broadcast/link/ - 403 Forbidden; at Request.handleResponseError (/Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/src/core/request.js:126:16) at Request.send (/Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/src/core/request.js:54:28) at async DirectThreadRepository.broadcast (/Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/src/repositories/direct-thread.repository.js:177:26) at async DirectThreadEntity.broadcast (/Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/src/entities/direct-thread.entity.js:192:26) at async DirectThreadEntity.broadcastLink (/Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/src/entities/direct-thread.entity.js:70:16) at async sendMessage (/Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/engine/send_text.js:11:12) at async /Users/davidesantangelo/Work/chorally/apis/instagram-private-api/dist/engine/send_text.js:16:5

YOUR WELL FORMATTED ERROR

YOUR OUTPUT GOES HERE

[Nerixyz]

This will be possible if #1334 is merged. But fow now you can use this:

const sendText = (entity: DirectThreadEntity, test: string) => (entity as any).broadcast({
  item: 'text',
  form: {
    text,
  },
});

You can leave out the as any if you’re not using Typescript.

[avalanche1]

@davidesantangelo did you solve it and how?