How to get enum declaration from type

Hi, i see that i can get the enum members - const members = enumDeclaration.getMembers();

but i have the type, how can i get the type declaration to get the members?

export enum Role {
  admin = "admin",
  user = "user"
}

export class User  {
  role: Role;
}

i looping other user properties and build my ajv scheme -

export const getParamSchema = (type: Type) => {
  if (type.isEnumLiteral()) {
    schema.type = "string";
    schema.enum = [];// here i want to add the enum members..
  }
}

thanks.

[dsherret]

@yantrab now that #916 is implemented you should be able to do:

nonNullableType.getUnionTypes().map(t => t.getLiteralValueOrThrow() as string)

[fasiha]

@dsherret forgive me for potentially hijacking this question, I feel like it’s very similar to my question. Happy to open a new issue if that’s better!

My question: is there a way to add enum or union members? I have the following:

import { Project, Node as TypeGuards } from 'ts-morph';
var project = new Project();
var sourceFile = project.createSourceFile(
  'file.ts',
  `const c = 'ccc';
  export type Foo = 'a'|'b'|typeof c;
  `,
);
var al = sourceFile.getTypeAliasOrThrow('Foo');
var ty = al.getType();
console.log(ty.getUnionTypes().map(t=>t.getLiteralValueOrThrow()))

and I can see the literal values of my union type Foo. Great. Now, what’s the way for me to add a new element to the union 'd' say?

(I see that object expressions have addPropertyAssignment for example, and wondering if there’s an equivalent for unions?)