How to convert to a `NodePath`?

I’m trying to create a transformer that will go from:

React.createElement(Foo, null);
React.createElement(Foo, { bar: "baz", onClick: this.divClicked });

React.createElement(
    Foo,
    { bar: "baz", onClick: this.divClicked },
    React.createElement("div", { foo: "bar" })
  );

to

<Foo></Foo>;
<Foo bar="baz" onClick={this.divClicked}></Foo>;

<Foo bar="baz" onClick={this.divClicked}>
    <div foo="bar">
    </div>
</Foo>

I’ve gotten the first two examples, but I’m confused on recursively handling the children.

My interactive codemod is here: http://felix-kling.de/esprima_ast_explorer/#/hb6iLO9hTe/4

If I change convertNodeToJSX to:

function convertNodeToJSX(node) { 
    if (!node) {
      return;
    }

    console.log(node);

   // other code

   const children = convertNodeToJSX(args[2]);

then I get printed out

NodePath {value: Object, parentPath: NodePath, name: "expression", __childCache: Object}
NodePath {value: Object, parentPath: NodePath, name: "expression", __childCache: Object}
NodePath {value: Object, parentPath: NodePath, name: "expression", __childCache: Object}
Object {type: "CallExpression", start: 175, end: 217, loc: i, callee: Object…}

So how can I convert the CallExpression to a NodePath? Wrapping the element with j() gives me:

e {_parent: undefined, __paths: Array[1], _types: Array[5]}

Or perhaps as a higher level question, is this even the right approach?

[fkling]

Recast (ast-types actually) provides two APIs: One lets you access the underlying “raw” AST node, with .value or .node, as you already know. The other gives you a NodePath instead of the raw AST node value.

Examples:

var args = path.value.arguments; // array of AST nodes
var args = path.get('arguments'); // NodePath representing the array of AST nodes

.get takes multiple arguments. To get the NodePath to the first AST node in arguments, you can do:

var pathToFirstArg = path.get('arguments', 0); // or args.get(0) from above

See also https://github.com/benjamn/ast-types#nodepath .

Wrapping the element with j() gives me …

j will always return a collection of NodePaths.

[cpojer]

Oh yeah, react-codemod is fine for React specific codemods.