Missing React.PropTypes.oneOfShape operator

import React from 'react';

let timeShape,
    placeholderShape;

timeShape = React.PropTypes.shape({
    type: React.PropTypes.oneOf(['time']).isRequired,
    date2: React.PropTypes.number.isRequired,
    url: React.PropTypes.string.isRequired,
    position: React.PropTypes.number.isRequired
});

placeholderShape = React.PropTypes.shape({
    type: React.PropTypes.oneOf(['placeholder']).isRequired,
    position: React.PropTypes.number.isRequired
});

export default React.createClass({
    propTypes: {
        times: React.PropTypes.arrayOf(React.PropTypes.oneOfShape([timeShape, placeholderShape])).isRequired
    },

    render: function () {
        return <div />;
    }
});

There is no way to validate whether times is an array where is each property if oneOfShape. Whats even worst, if you use oneOfType in the latter example, it produces no error and does not validate the data as expected.

[probablyup]

React.PropTypes.arrayOf(
    React.PropTypes.oneOfType(
        [
            React.PropTypes.shape({}),
            React.PropTypes.shape({})
        ]
    )
)

(just making @JohnyDays example more legible)

[JohnyDays]

Glad it worked out! 🚀