How does the `synchronize` function work?
See original GitHub issue❓ Questions and Help
I found that in your codes you use synchronize
helper function to synchronize gpus. I am not familiar with the usage of torch.distributed.deprecated
, and I am trying to understand how does the following codes actually work.
def synchronize():
"""
Helper function to synchronize between multiple processes when
using distributed training
"""
if not torch.distributed.deprecated.is_initialized():
return
world_size = torch.distributed.deprecated.get_world_size()
rank = torch.distributed.deprecated.get_rank()
if world_size == 1:
return
def _send_and_wait(r):
if rank == r:
tensor = torch.tensor(0, device="cuda")
else:
tensor = torch.tensor(1, device="cuda")
torch.distributed.deprecated.broadcast(tensor, r)
while tensor.item() == 1:
time.sleep(1)
_send_and_wait(0)
# now sync on the main process
_send_and_wait(1)
I get some questions here.
- Will
broadcast
block the main process until all other processes receive the tensor? What are the behaviors of this function in different type of processes? - Why use
_send_and_wait(1)
at the end of this function? I know that rank 0 is the master, but what is special for rank 1?
Issue Analytics
- State:
- Created 5 years ago
- Comments:29 (27 by maintainers)
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Oh, yes, I didn’t use coco and error did not always happen. It happens more frequently when I run multiple copy of inference codes on a single machine at the same time. All 8 GPUs are the same. I use 0-3 to run a copy of codes and 4-7 to run another. I think maybe the cause is the high workload of CPU.
Yes, this happens because of the lazy initialization in the NCCL backend. The faster process will try to create a new NCCL communicator and is waiting for the slower process to do the same. This times out after 5 minutes. This timeout is set on the k/v store (be it a file backed store or TCP store where a single process acts as server) and is currently not configurable.
This is a dup of pytorch/pytorch#16225 so this one can be closed and we can continue discussion there.