Polymorphic deserialization with `EXTERNAL_PROPERTY` fails if type property not marked as property

I have class as follows

class XYZ {
    private String type;

    private TypeSpecific typeSpecific;

    public TypeSpecific getTypeSpecific() {
        return typeSpecific;
    }

    @JsonTypeInfo(
		use = JsonTypeInfo.Id.NAME, 
		include = JsonTypeInfo.As.EXTERNAL_PROPERTY, 
		property = "type"			
		)
    @JsonSubTypes({		
		@JsonSubTypes.Type(value = ATypeSpecific.class, name = "a")
    })
    public void setTypeSpecific(TypeSpecific typeSpecific) {
        this.typeSpecific = typeSpecific;
    }
}

Class ATypeSpecific extends TypeSpecific.

I want to deserialize JSON {"type":"b"} where typeSpecific will be set as null in object. But I am getting following exception:

com.fasterxml.jackson.databind.JsonMappingException: Missing property 'typeSpecific' for external type id 'type'

How do I deserialize above mentioned JSON into the object? If @JsonTypeInfo requires ‘typeSpecific’ property during deserialization, then is there a way to add it into JSON before deserialization?

Dependency versions: jackson-annotations: 2.7.0 jackson-core: 2.7.4 jackson-databind: 2.7.4

[buremba]

@cowtowncoder The type id may be useful by itself so don’t assume that type id is there just for deserializing another value. For example, here is our use-case: We have reports and each report has a type. Depending on that type, each report has options and we use different classes for different report types. We also have two different endpoints in our API server; list and get. The list reports the report names and types but not options because we just need to list the reports in a table. When the user clicks a report, we fetch the options from the server and return the data to the user.

[cowtowncoder]

@buremba Ok. In that case I would need a reproduction of the problem (in plain Java) since test for #1341 passes as expected at this point.