Bypass Jailbreak using Liberty Lite
See original GitHub issueHi,
I want to ask, can this lib be bypassed using Liberty Lite?
I want to make sure that jail-monkey prevents bypass from any tools, including Liberty Lite.
Thank you.
Issue Analytics
- State:
- Created 3 years ago
- Comments:7
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Share me your personal Id. I will communicate with you On Wednesday, 14 April, 2021, 04:32:51 pm GMT+8, harshitDewan @.***> wrote:
@anupamhore
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Hi, Yes I have found a solution. Please implement from the below steps.
{
…
….
//Jailbreak detection, if it is true, show alert, then exit app
if (!isSecurityCheckPassed()) {
UIAlertController *alertController = [UIAlertController
alertControllerWithTitle:@“Jailbroken Device is Detected”
message:@“Your device might have been modified. In order to protect your privacy, we will not run the application on this device. It is recommended to have your device checked by the device manufacturer.”
preferredStyle:UIAlertControllerStyleAlert];
UIAlertAction *cancelAction = [UIAlertAction actionWithTitle:@“Ok”
style:UIAlertActionStyleDefault
handler:^(UIAlertAction *action) {
exit(1);
}];
[alertController addAction:cancelAction];
[self.window.rootViewController presentViewController:alertController animated:YES completion:nil];
}
……
……
}
Considering you already have the jailbreak code in the react native side with the jail monkey plugin, use this in the xcode. It will work
My Pen Test also failed because the guys were using Liberty Lite. Is there any way to prevent this
@anupamhore did you found any possible solution yet ?
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