Call a model's method when querying for a field

Let’s say I have the following query:

query {
  spreadsheet(id: 50) {
    name, 
    user {
      id, username
    },
    rows {id} # this is the foreign key that I need to call a function on 
  }
}

and my spreadsheet Model looks like:

class Spreadsheet:
  objects = SpreadsheetManager()
  user = models.ForeignKey(User)
  name = models.CharField()
  rows = model.ForeignKey(RowGenerator)
  ...

currently my query class looks like:

class Query(graphene.ObjectType):

  spreadsheet = graphene.Field(SheetType,
        id=graphene.Int(),
        name=graphene.String()
    )

  resolve_sheet(self, info, **kwargs):
        sheet_id = kwargs.get('id')
        # name = kwargs.get('name')

        if sheet_id is not None:
            return Sheet.objects.select_related('user','rows').prefetch_related('projects').get(id=sheet_id)

        return None

rows is a foreign key to an object, that upon calling a function generate_rows(), generates row data. Currently, my query returns the id of the foreign key, but what I want to do is to call a function on that object, (rows.generate_rows(), for example). How would it be possible to tell graphene to call that function on the field, once we retrieve it from the database?

[Mhs-220]

@BossGrand Hey! is there any way to filter rows? for example, if we have person instead of rows, and it has first name and last name… is there anyway to do this? :

class PersonNode ( DjangoObjectType ):
	class Meta:
		model = Person
		interfaces = ( graphene.relay.Node, )
		filter_fields = {
			'full_name': ['exact', 'icontains', 'istartswith'],
		}

	full_name = graphene.String()
	def resolve_full_name ( instance, info, **kwargs ):
		return " ".join([instance.first_name, instance.last_name])

[kneufeld]

@Mhs-220 did you ever figure out how to do this? I’m in the same boat.