Defaulting the first param / paging by default

I have the following snippet:

def resolve_products(self, info, **kwargs):
    return Product.objects.all()

I want to return 100 results by default. I notice that if I specify say first: 30 in my query

{ products (first: 30 ){} } that first appears in kwargs.

I then tried setting kwargs['first'] to 100 if no first key is found, but it has no effect.

How do I default first so all results do not get returned by default

[gabelimon]

@muriloacs the easiest way that I’ve found to make this happen is to create a new connection field with an overridden connection_resolver. This is untested as I don’t need it right now but it should be about right.

from graphene_django.filter import DjangoFilterConnectionField


class AutoPagedDjangoFilterConnectionField(DjangoFilterConnectionField):
    @classmethod
    def connection_resolver(
        cls,
        resolver,
        connection,
        default_manager,
        max_limit,
        enforce_first_or_last,
        filterset_class,
        filtering_args,
        root,
        info,
        **args
    ):
        args['first'] = args.get("first", 40)
        return super().connection_resolver(
            cls,
            resolver,
            connection,
            default_manager,
            max_limit,
            enforce_first_or_last,
            filterset_class,
            filtering_args,
            root,
            info,
            **args
        )

[jkimbo]

@gabelimon you can set a default value of a connection field like this:

from graphene import ObjectType, Int

class Query(ObjectType):
	users = DjangoFilterConnectionField(User, first=Int(default_value=100))