Question about querying a single resource with flask sqlalchemy example.

I have followed the example at http://docs.graphene-python.org/projects/sqlalchemy/en/latest/tutorial/#testing-our-graphql-schema and have a question.

I can issue the following query to list all employees and their departments.

{
  allEmployees {
    edges {
      node {
        name
        department {
          name
        }
      }
    }
  }
}

I would like to be able to query a single employee name and their department name by employee id. I can query using the Node interface, but that doesn’t allow me to access Employee name field. Am I supposed to “cast” this to the specific Employee type to do that? What I would like is something like:

{
  employee(id: "someid") {
    name
    department {
      name
    }
}

Is this reasonable or am I “doing it wrong”? What is best practice for accessing a single employee using the Relay connections/nodes/edges paradigm?

Many thanks in advance!

[tlbjr]

You could do something like this.

find_employee = graphene.Field(lambda: Employee, name=graphene.String())

def resolve_find_employee(self, args, context, info):
    query = Employee.get_query(context)
    name = args.get('name')
    return query.filter(EmployeeModel.name == name).first()

Thanks for the pointers @navinesh. This worked great:

class Query(graphene.ObjectType):
    ...
    find_employee = graphene.Field(lambda: Employee, name=graphene.String())

    def resolve_find_employee(self, info, **kwargs):
        query = Employee.get_query(info)
        name = kwargs.get("name")
        return query.filter(EmployeeModel.name == name).first()

query FindEmployeeByName($name: String = "Tracy") {
    findEmployee(name: $name) {
        id
        name
        department {
            name
        }
    }
}

[navinesh]

You could do something like this.

find_employee = graphene.Field(lambda: Employee, name=graphene.String())

def resolve_find_employee(self, args, context, info):
    query = Employee.get_query(context)
    name = args.get('name')
    return query.filter(EmployeeModel.name == name).first()