Task 'default' is not in your gulpfile

Hello, I’m running node 0.12.7, npm 2.11.3 on Win7, and running this code returns a ‘Task default is not in your gulpf file’:

[11:43:50] Using gulpfile ~\Web\mywebsite\gulpfile.js
[11:43:50] Task 'default' is not in your gulpfile
[11:43:50] Please check the documentation for proper gulpfile formatting

This is the code

var gulp = require('gulp'),
watch = require('gulp-watch'),
jade = require('gulp-jade'),
less = require('gulp-less');

// functions ----------------------

gulp.task('default', ['compile']);

gulp.task('compile', function() {
    return gulp.src('./less/*.less')
    .pipe(less())
    .pipe(gulp.dest('./css'));
})

This are my installed modules:

├── browser-sync@2.7.13
├── gulp@3.9.0
├── gulp-coffee@2.3.1
├── gulp-jade@1.0.1
├── gulp-less@3.0.3
├── gulp-plumber@1.0.1
├── gulp-stylus@2.0.5
├── gulp-watch@4.3.3
├── lost@6.5.0
└── require-dir@0.3.0

Thanks

[ilovezy]

maybe you should put the

gulp.task(‘default’, [‘compile’]);

after the compile task was defined? you can not bind the compile task into default before decare it?

[Romanx]

This is related to where the tasks are defined prior to their use. JS natively hoists variables as can be found here but i’m not sure if that is different for node/gulp i’d assume not.

This is another good example explaining complications here.

I think this should be closed as theirs nothing gulp can really do. You could use manual hoisting by defining name function variables as opposed to defining them in gulp.task that should cause them to be hoisted.