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ExecutionTime.forCron prints to system out

See original GitHub issue

cron-utils 9.0.1

reproducer (scala)

  val cronDefinition = CronDefinitionBuilder.instanceDefinitionFor(CronType.QUARTZ)
  val parser = new CronParser(cronDefinition)
  val cron = parser.parse("0 0 0 1 1 ? 2000")
  ExecutionTime.forCron(cron)

output

We for an class com.cronutils.model.time.generator.OnFieldValueGenerator builder

Issue Analytics

State:
Created 4 years ago
Comments:11 (7 by maintainers)

Top GitHub Comments

3reactions

jmrozaneccommented, Oct 12, 2019

@Fantazjatyk @marcoslarsen @francisdb version 9.0.2 was released with this fix. Enjoy! 😄

1reaction

jmrozaneccommented, Jul 11, 2020

@francisdb @marcoslarsen @Fantazjatyk a new version was released with the fixes. Please find details here Thank you for contributing to cron-utils!

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