How do write a subquery?

Hi. @tgriesser . first of all congratulations on the superb job you all have been doing creating this tool. It looks amazing and it’s working quite well.

for example (for postgres)

SELECT
   *
 FROM
   tbl_a LEFT join (
      SELECT 
          id, name 
      FROM 
           tbl_b
      GROUP BY 
           id, name
   )  AS tbl_b on tbl_a.id = tbl_b.id

now

Knex('tbl_a').select('*').join(
                Knex.Raw('(SELECT id, name FROM tbl_b GROUP BY id, name) AS tbl_b')
                ,'tbl_a.id', '=', 'tbl_b.id', 'LEFT');

I want to create without the Raw method.

Is it possible to other, using the USING?

thank you.

[ivan-kleshnin]

It is possible:

// [users] to [offers] :: [1] to [n]

let countedVisibleOffers = knex.select("user_id")
  .count("* as total")
  .from("offers")
  .groupBy("user_id")
  .as("visible_offers");

console.log(
  knex.select("*", "visible_offers.total")
    .from("users")
    .leftOuterJoin(countedVisibleOffers, "visible_offers.user_id", "users.id")
    .where(...)
    .orderBy(...)
    .toString()
);

[tgriesser]

Hi @dai-yamashita - glad you’re liking it!

Currently there isn’t support for doing sub-queries for joins, and the Knex.Raw would be the best way to go about it - though there’s no reason that couldn’t be allowed - I’ll look into adding a way to do it using an independent query:

Would this be what you’re looking for?

Knex('tbl_a').select('*').join(
   Knex('tbl_b').select('id', 'name').groupBy('id', 'name'),
   'tbl_a.id', 
   '=', 
   'tbl_b.id', 
   'LEFT'
);