TypeScript does not set function name for MethodDeclarations

This issue has been asked as a question on StackOverflow.

I have a TypeScript class, and I’m doing some metaprogramming where I need to be able to access instance.func.name, however TypeScript omits the function name in the compiled JS.

TypeScript:

class ClassName {
    // ... 
    func(): ReturnType {
        // ...
    }
}

Compiled JavaScript:

// ...
ClassName.prototype.func = function () {
    // ... 
};

Desired JavaScript:

ClassName.prototype.func = function func() {
    // ...                          ^^^^
};

Not sure if this is a bug or by design, but the source of the result is emitter.ts.

A proposed solution on StackOverflow was:

// src/compiler/emitter.ts:4671
function shouldEmitFunctionName(node) {
    if (node.kind === 173 /* FunctionExpression */) {
        // Emit name if one is present
        return !!node.name;
    }
    if (node.kind === 213 /* FunctionDeclaration */) {
        // Emit name if one is present, or emit generated name in down-level case (for export default case)
        return !!node.name || languageVersion < 2 /* ES6 */;
    }

    // MODIFIED
    if (node.kind === 143 /* MethodDeclaration */) {                    
        return true;
    }                                                        
}

[jannesiera]

Bump

[Manish3177]

Hello, are there any updates on this issue? According to the latest activity above (on 8/31/2017), it was supposed to be added to TypeScript 2.6 but it isn’t there in it. Also, if it’s not too late, I would like to suggest that the name should include the class name as well (ClassName$functionName, for example). In large projects where the same function is used by several classes (for example when overriding a function from a base class), the function name alone isn’t sufficient to uniquely identify the actual function. It would be even better if there was a way to control the prefix.