The Python path in your debug configuration is invalid.

Environment data

• VS Code version: 1.45.1
• Extension version (available under the Extensions sidebar):2020.5.80290
• OS and version: win10
• Python version (& distribution if applicable, e.g. Anaconda): python-3.8.3-embed-amd64
• Type of virtual environment used (N/A | venv | virtualenv | conda | …): N/A

Expected behaviour

vscode can find python interpreter

Actual behaviour

vscode cann’t found python interpreter

Steps to reproduce:

1. download python-3.8.3-embed-amd64.zip and Unzip it

2. write sample python code and use vscode opened it:

print(123)

1. create launch.json

{
    // Use IntelliSense to learn about possible attributes.
    // Hover to view descriptions of existing attributes.
    // For more information, visit: https://go.microsoft.com/fwlink/?linkid=830387
    "version": "0.2.0",
    "configurations": [
        {
            "name": "Python: cureent file",
            "type": "python",
            "request": "launch",
            "program": "${file}",
            "console": "integratedTerminal",
            "pythonPath": "e:/tools/re/python-3.8.3-embed-amd64/python.exe"
        },
    ]
}

1. press f5 to debug it
2. message fatal:

[farshad6218]

Follow The Microsoft guide to solve your problem.

https://code.visualstudio.com/docs/python/environments > “To select a specific environment, use the Python: Select Interpreter command from the Command Palette (Ctrl+Shift+P).”

[scalavision]

I had wrong path to python interpreter in the user settings. When manually setting the path to the interpreter via the gui, to be used inside the dev container, it silently failed. I found it in the Python log output eventually. A popup for this error would have been very helpful 😅