only produce the path element, not the whole file

I would like to embed the QR svg element produced by this library in my own svg producing software, and the only way I see to do that, is to write the file into a StringIO, then extracting the element I need.

according to the docstring for QRCode.svg,

If only the code itself is desired, set the xmldecl to false. This will result in a fragment that contains only the “drawn” portion of the code.

however, if I do that, I only get rid of the leading <?xml version="1.0" encoding="UTF-8"?>, not also the root svg element. I would like the naked path element, and I would like it returned in a string, not written to a file.

[heuer]

If you use BytesIO, you’ll have to decode the value into the used encoding (default: UTF-8) before passing it into re.search / re.match

    def __call__(self, x, y, text, scale=1, encoding='utf-8'):
        qr = self.pyqrcode.create(text)
        self.buffer.truncate(0)
        self.buffer.seek(0)
        qr.svg(self.buffer, xmldecl=False, quiet_zone=0, scale=scale, encoding=encoding)
        match = self.pattern.search(self.buffer.getvalue().decode(encoding))
        result_list = [match.group(1)]
        if x != 0 or y != 0:
            result_list.insert(0, '<g transform="translate(%s,%s)">' % (x, y))
            result_list.append('</g>')
        return '\n'.join(result_list)

[heuer]

Omitting the SVG element isn’t possible. It’s possible to omit additionally the namespace delaration; this is useful if you want to embed the generated QR Code in HTML files.

Anyway, extracting the path should be trivial.

BTW, you don’t have to write to a file:

>>> import io
>>> import pyqrcode
>>> qr = pyqrcode.create('Test')
>>> out = io.BytesIO()
>>> qr.svg(out, scale=10, xmldecl=False, svgns=False)
>>> out.getvalue()