'Property<T, U>' has no properties in common with type 'TypedPropertyDescriptor<U>

Hi guys,

when trying to compile my typescript file, I get to see this error.

node_modules/tns-core-modules/ui/core/properties/properties.d.ts(48,14): error TS2559: Type 'Property<T, U>' has no properties
in common with type 'TypedPropertyDescriptor<U>'.

following through on this error, and implementing one of the method decleared in this interface TypedPropertyDescriptor<U> in Property<T, U> the error goes away and I’m able to compile successfully.

interface TypedPropertyDescriptor<T> {
    enumerable?: boolean;
    configurable?: boolean;
    writable?: boolean;
    value?: T;
    get?: () => T;
    set?: (value: T) => void;
}

export class Property<T extends ViewBase, U> implements TypedPropertyDescriptor<U> {
    constructor(options: PropertyOptions<T, U>);

    public readonly getDefault: symbol;
    public readonly setNative: symbol;
    public readonly defaultValue: U;
    public register(cls: { prototype: T }): void;
    public nativeValueChange(T, U): void;
    public isSet(instance: T): boolean;
}

Can this be fixed, i’ll rather not have to do this (edit) in my node_modules/tns-core-modules/ui/core/properties/properties.d.ts file.

[NickIliev]

The error you are hitting is most likely caused by a mismatch of your TypeScript version and the usage of PropertyDescriptors with the syntax supported in previous TS versions`. If you are using TypeScript 2.4.1 you might try to downgrade to 2.3.4. More information here and here.

Once you downgrade the version of your TypeScript, remove node_modules and rebuild your project. Let me know if that resolved your issue.

[bmargevicius]

adding “skipLibCheck”: true, to tsconfig helped me get it to build.

“compilerOptions”: {
“skipLibCheck”: true,