Question - is it possible to order index by word occurrences (hits)

I’m trying to do a simple blog search that sorts search results by keyword occurrences. The default FlexSearch behavior seems to try to retain the original order of the content as it was added to the Index… which makes sense for a book. Is this possible with flexsearch@0.6.x or flexsearch@0.7.x?

Here is a simple example, where each page just a ‘id’ and the ‘body’. When I search for a keyword, ‘cat’, I want the posts with the most occurrences of ‘cat’ first.

import FlexSearch from "flexsearch"
type IndexableDocument = Record<string, unknown>

const index = FlexSearch.create<IndexableDocument>({})

const document = [
  { id: `threecat`, body: `cat meows. cat stretch. cat sleep.` },
  { id: `onecat`, body: `cat is still asleep` },
  { id: `catcatdogdog`, body: `dog barks at cat. cat runs from dog.` },
  { id: `onedog`, body: `dog sleeps` },
  { id: `threedog`, body: `dog woofs. dog chases tail. dog sleeps` },
]
document.forEach(({ id, body }) => {
  index.add(id as number, body)
})

index.search("cat") // goal: [ 'threecat', 'catcatdogdog', 'onecat' ]
index.search("dog") // goal: [ 'threedog', 'catcatdogdog', 'onedog' ]

// actual flexsearch@0.6.x output, respects order of original content
// cat: ["threecat","onecat","catcatdogdog"]
// dog: ["catcatdogdog","onedog","threedog"]

[ts-thomas]

Good news, it is now supported by the option “boost”: https://github.com/nextapps-de/flexsearch#index-options

Example:

const index = new Index({ 
    boost: function(words, term, index){
        let factor = 0;
        for(let i = 0; i < words.length; i++){ 
            if(words[i] === term) factor++; 
        }
        return factor || 1;
    }
});

[mmm8955405]

term ，Appear other words！！！！…