execute a job at every 3 hours of every day -help

Hi, noob to this cron world I want o execute a job at every 3 hours of every day

var rule = new schedule.RecurrenceRule();
rule.dayOfWeek = [0,6];
rule.hour = 17; // can i add multiple times [06,9,12,15,...]
rule.minute = 0;

var j = schedule.scheduleJob(rule, function(){
  console.log('Today is recognized by Rebecca Black!');
});

or which seem too long

var rule1 = new schedule.RecurrenceRule();
rule1.dayOfWeek = [0,6];
rule1.hour = 06; // set at 6 am
rule1.minute = 0;

var rule2 = new schedule.RecurrenceRule();
rule2.dayOfWeek = [0,6];
rule2.hour = 09; // set at 9 am
rule2.minute = 0;
...

var j = schedule.scheduleJob(rule1, function(){
  console.log('Today is recognized by Rebecca Black!');
});
var j = schedule.scheduleJob(rule2, function(){
  console.log('Today is recognized by Rebecca Black!');
});
..

any help would be appreciated

[rguedes]

Hi, Try this: var j = schedule.scheduleJob('0 0 */3 * *', function(){ console.log('The answer to life, the universe, and everything!'); });

[santigimeno]

@vcasadei use a Range:

rule.hour = new schedule.Range(19, 22);