to_pickle() got an unexpected keyword argument 'protocol'
See original GitHub issueCode Sample, a copy-pastable example if possible
df.to_pickle(path=filename", compression='infer', protocol=2)
Problem description
to_pickle() got an unexpected keyword argument 'protocol'
```
#### Expected Output
None.
#### Output of ``pd.show_versions()``
<details>
INSTALLED VERSIONS
------------------
commit: None
python: 3.6.1.final.0
python-bits: 64
OS: Linux
OS-release: 4.4.0-43-Microsoft
machine: x86_64
processor: x86_64
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: en_US.UTF-8
pandas: 0.20.2
pytest: None
pip: 9.0.1
setuptools: 27.2.0
Cython: 0.25.2
numpy: 1.13.1
scipy: 0.19.1
xarray: None
IPython: None
sphinx: None
patsy: 0.4.1
dateutil: 2.6.0
pytz: 2017.2
blosc: None
bottleneck: None
tables: 3.3.0
numexpr: 2.6.2
feather: 0.4.0
matplotlib: 2.0.2
openpyxl: None
xlrd: None
xlwt: None
xlsxwriter: None
lxml: None
bs4: None
html5lib: None
sqlalchemy: None
pymysql: None
psycopg2: 2.7.1 (dt dec pq3 ext lo64)
jinja2: None
s3fs: None
pandas_gbq: None
pandas_datareader: None
</details>
Issue Analytics
- State:
- Created 6 years ago
- Comments:5 (2 by maintainers)
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Top GitHub Comments
I am facing the same issue , can you please elaborate the solution to this. It will be a great help !
whl don’t exist for conda - that is a pip installation
closing as an installation issue u less it’s repo on a new environment