FigureWidget does work not from inside an if statement

Encountered in Jupyter Lab.

Take the following 2 cases:

fig = go.FigureWidget()
fig

&

silent=False

if not silent:
    fig = go.FigureWidget()
    fig

The first one produces a figure, the second one does not. Why don’t they behave similarly?

If I use the @interact decorator in the second case. e.g.

if not silent:
    fig = go.FigureWidget()
    fig.add_scatter()

    @interact(s=(3,5))
    def update(s=3):
        with fig.batch_update():
            fig.data[0].y = np.random.normal(size=s)
    fig

the slider appears, but the figure does not.

[jasongrout]

display is what IPython calls automatically on the last top-level expression to display it in your first example.

[jasongrout]

You may be able to use the display command:

if True:
    fig = go.Figure()
    display(fig)

(if you have an older version of ipython, you may need to import it: from IPython.display import display