2.x: confused of method takeLast(long,TimeUnit)

I’m a little confused about takeLast(long, TimeUnit). When executing the following code, each time the output order is supposed to be N digits in the last time window, but in fact the output results are inconsistent with the ideal state.

Code

 public static void main(String[] args) {
        ArrayList<Integer> ints = new ArrayList<>();
        for (int i = 0; i < 100; i++) {
            ints.add(i);
        }
        Observable.fromIterable(ints)
                .takeLast(1,TimeUnit.NANOSECONDS)
                .subscribe(longs->{
                    System.out.println(longs);
                });
        try {
            Thread.sleep(100000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }

Result

[akarnokd]

Because onComplete can happen much later than the previous onNext, thus that value is now out of the time window.

[FlyingPigQAQ]

@akarnokd Hello! I would like to know that the takeLast() method is to get the data of the last window that was sent. We already got the data of the last window in the OnNext() method, so why do we have to make another time difference judgment in the onComplete() method