findAll WHERE, using previously defined sequelize.fn attribute

Hello,

I have two tables: products and brands and I am trying to fetch all brands where the associated product count is superior to 0.

So far I’ve been able to count the associated products and return that with the data as the attribute “product_count”, using a sequelize.fn:

models.Brand.findAll({
    order: 'id ASC',
    attributes: ['id', 'name', 'slug', [sequelize.fn('COUNT', sequelize.col('products.id')), 'product_count']],
    include: [{model: models.Product, attributes:[]}],
    group: ['brand.id']
})

This creates the following query (which works perfectly):

SELECT "brand"."id", "brand"."name", "brand"."slug", COUNT("products"."id") AS "product_count" 
FROM "brands" AS "brand" 
LEFT OUTER JOIN "products" AS "products" ON "brand"."id" = "products"."brand_id" 
GROUP BY "brand"."id" 
ORDER BY id ASC;

Now, instead of returning all of the brands, I’d like to only return brands where the product count is superior to 0. I tried this:

models.Brand.findAll({
    order: 'id ASC',
    attributes: ['id', 'name', 'slug', [sequelize.fn('COUNT', sequelize.col('products.id')), 'product_count']],
    include: [{model: models.Product, attributes:[]}],
    group: ['brand.id'],
    where: {
        'product_count': {
            $gt: 0
        }
    }
})

But it spits out an error:

{"error":{"name":"SequelizeDatabaseError","message":"column brand.product_count does not exist"}}

With the query being:

SELECT "brand"."id", "brand"."name", "brand"."slug", COUNT("products"."id") AS "product_count" 
FROM "brands" AS "brand" 
LEFT OUTER JOIN "products" AS "products" ON "brand"."id" = "products"."brand_id" 
WHERE "brand"."product_count" > 0 
GROUP BY "brand"."id" 
ORDER BY id ASC;

Is it not possible to reference an attribute previously defined with sequelize.fn in the where? Is there a solution that I am not aware of?

Thank you

[felixfbecker]

try sequelize.where('product_count', {$gt: 0})

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