How to get multiple result sets by calling a stored procedure using sequelize?

I noticed someone asked the same question, but not answered. Want to try this question here. To help understanding my question, the code below is an example to call stored procedure using sequelize:

sequelize.query(CALL GetLatestNews();, { type: sequelize.QueryTypes.RAW }) .then(function(results) { console.log(JSON.stringify(results)); })

The stored procedure returns 3 result sets. However, only the first result set being returned.

I tried to change the line .then(function(results) { to .spread(function(results, metadata) {

This time, results is holding only the first row of the first result set, while metadata holding the second row of the first result set.

Any help is highly appreciated!

[indrajeet0510]

I don’ think so sequelize is having this kind of problem.

First you have to make sure that multipleStatements should be true. Next whenever your procedure is returning more than one result set, your code should look like this

var query = "CALL someprocedure(:userId,:status)";
sequelize.query(query,{ replacements : { userId : userId, status : status}, type : sequelize.QueryTypes.SELECT}

I got multiple resultset into same results in array form using this.

[ghost]

For me entity is returning the merged result and not seperate arrays from SP. I am using nodejs, sequelize and sql server model.sequelize.query(‘AssetCountAsPerStatus’, { multipleStatements: true, type: model.sequelize.QueryTypes.SELECT }) .then(data => { console.log(‘data’, data); var res_1 = Object.keys(data[0]); var res_1_List = []; for (var i = 0; i < res_1.length; i++) { res_1_List.push(data[0][i]); }

            var res_2 = Object.keys(data[1]);
            var res_2_List = [];
            for (var j = 0; j < res_2.length; j++) {
                res_2_List.push(data[1][j]);
            }
            return res.status(200).json({ "res_1_List": res_1_List, "res_2_List": res_2_List })
        })