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Default room name is not socket id

See original GitHub issue

I’m using socket.io 1.4.5.

if I do

io.to(socketId).emit('some msg');

the message will not be emitted.

after digging a little bit I found that I should prepend /# before socke id.

socketRoomName = '/#' + socketId;
io.to(socketRoomName).emit('some msg');

Issue Analytics

State:
Created 8 years ago
Comments:6 (3 by maintainers)

Top GitHub Comments

2reactions

baconbradcommented, Mar 8, 2016

Also io.emit('some msg'); will send it to everyone in the default room. So if you have no use for multiple rooms you can omit it’s usage completely from your code and let socket.io handle it.

Take note ‘some msg’ is the event. So you might be looking to do something like io.emit('msg', 'some msg'); instead and listen for msg on the client side.

1reaction

ghostcommented, Mar 11, 2016

You’re right. Just ignore the guy above.

I lost two hours trying to figure out what was going on. Turns out when I did THISID = socket.id it got stored as “EgdohcmzQZnc_FzHAAAA” instead of (‘/#’ + “EgdohcmzQZnc_FzHAAAA”) which is the true socket id. So server side socket.id is /#EgdohcmzQZnc_FzHAAAA, but client side socket.id is EgdohcmzQZnc_FzHAAAA. Who is responsible for this?

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