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Remove empty anyOf

See original GitHub issue

I have the following schema to add support for mongodb ObjectId type:

export const objectId = z.union([
  z.instanceof(ObjectId),
  z
    .string()
    .regex(/^[a-f0-9]{24}$/, { message: "This string does not look like an ObjectId()" })
    .transform((s) => new ObjectId(s))
]);

This translates to the following schema:

{
  anyOf: [ {}, { type: 'string', pattern: '^[a-f0-9]{24}$' } ]
}

The issue is that {} allows for any input. I think it would be more appropriate to imply that z.instanceOf() cannot be translated into a JSON Schema and therefore should never be able to match anything somehow.

Does that make any sense?

Issue Analytics

State:
Created a year ago
Comments:5 (3 by maintainers)

Top GitHub Comments

1reaction

qraynaudcommented, Sep 23, 2022

Hey! This seems like a reasonable option at lest for the time being yes.

0reactions

StefanTerdellcommented, Sep 23, 2022

@qraynaud Hey, I just released 3.18.1 which adds a strictUnion option. Let me know if this solves your problem. If so I think we can close this

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