DuplicateWidgetID when you change the state of a widget with a button

Summary

There is a button “change” that should change the state of a checkbox from True to False. If it was True by default and then you click the button, then it is changing. But if it was False by default and then a user checked and made it True, then there is DuplicateWidgetID exception when you click the “change” button.

Steps to reproduce

import streamlit as st

a = st.empty()
value = a.checkbox(label='test', value=False)
# user checks the checkbox => value is True again
if st.button('change'):
    value = a.checkbox(label='test', value=False)
    # here we have an error "DuplicateWidgetID: There are multiple identical st.checkbox widgets with the same generated key."

Expected behavior:

I expect that the checkbox will change the value from True to False.

Actual behavior:

DuplicateWidgetID Excetion

Is this a regression?

don’t know

Debug info

• Streamlit version: Streamlit, version 0.60.0
• Python version: Python 3.7.6
• Using Conda: yes
• OS version: macOS 10.15.4 (19E287)
• Browser version: 84.0.4147.135 (Official Build) (64-bit)

[nthmost]

Yep, repro’d just now. Thanks for the sample code and nice writeup!

[kmcgrady]

Ah Thanks @Musalappagaridevendrareddy ! This has been resolved with our new state model. Your example does work as expected. This can also be handled without st.empty and using callbacks (run before the script run).

import streamlit as st

value = st.checkbox(label='test', value=False, key='test')

def handle_click():
    st.session_state.test = False

st.button('change', on_click=handle_click)