Segfault on creating a Ctx
See original GitHub issueInstallation using conda with Python 3.6.2 on Ubuntu 16.04.
tiledb 1.2.2 h650255c_2 conda-forge
tiledb-py 0.1.1 py36_0 conda-forge
Trying to create a Ctx
causes a segfault:
In [1]: import tiledb
In [2]: ctx = tiledb.Ctx()
*** Error in `/home/nezar/miniconda3/envs/py36/bin/python': free(): invalid pointer: 0x00007f1092c5bec0 ***
======= Backtrace: =========
/lib/x86_64-linux-gnu/libc.so.6(+0x777e5)[0x7f109ef5c7e5]
/lib/x86_64-linux-gnu/libc.so.6(+0x8037a)[0x7f109ef6537a]
/lib/x86_64-linux-gnu/libc.so.6(cfree+0x4c)[0x7f109ef6953c]
/home/nezar/miniconda3/envs/py36/lib/python3.6/site-packages/tiledb/../../../libtiledb.so(+0x86e39)[0x7f10939cae39]
/home/nezar/miniconda3/envs/py36/lib/python3.6/site-packages/tiledb/../../../libtiledb.so(+0x8cdcc)[0x7f10939d0dcc]
/home/nezar/miniconda3/envs/py36/lib/python3.6/site-packages/tiledb/../../../libtiledb.so(+0x9f5f8)[0x7f10939e35f8]
/home/nezar/miniconda3/envs/py36/lib/python3.6/site-packages/tiledb/../../../libtiledb.so(+0x173cc1)[0x7f1093ab7cc1]
/home/nezar/miniconda3/envs/py36/lib/python3.6/site-packages/tiledb/../../../libtiledb.so(tiledb_ctx_create+0xd1)[0x7f109399d011]
/home/nezar/miniconda3/envs/py36/lib/python3.6/site-packages/tiledb/libtiledb.cpython-36m-x86_64-linux-gnu.so(+0x89ec4)[0x7f1093db6ec4]
/home/nezar/miniconda3/envs/py36/bin/../lib/libpython3.6m.so.1.0(+0xda2ac)[0x7f109febe2ac]
/home/nezar/miniconda3/envs/py36/bin/../lib/libpython3.6m.so.1.0(_PyObject_FastCallDict+0x9e)[0x7f109fe4fc1e]
...
Issue Analytics
- State:
- Created 5 years ago
- Comments:6 (4 by maintainers)
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Top GitHub Comments
@manolinux I think your issue is different than the one above. The illegal instruction issue hints that the conda toolchain compiled with SSE or AVX vector instructions that your platform does not support.
Hi @nvictus, this looks to be an internal TileDB bug from the last version. We are working on getting ready for the next release (1.3.0) next week and I think this should be addressed.
I’ll leave this issue open until I can reproduce / confirm.