Raises an exception if a duplcate status is posted, documentation suggests otherwise

If update_status is called with a duplicate status, a TweepError is raised:

File "/usr/local/lib/python2.7/dist-packages/tweepy/api.py", line 194, in update_status
    )(post_data=post_data, *args, **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/tweepy/binder.py", line 245, in _call
    return method.execute()
  File "/usr/local/lib/python2.7/dist-packages/tweepy/binder.py", line 229, in execute
    raise TweepError(error_msg, resp, api_code=api_error_code)
tweepy.error.TweepError: [{u'message': u'Status is a duplicate.', u'code': 187}]

Although the documentation says “Statuses that are duplicates or too long will be silently ignored.”

[fitnr]

You can use an if block inside the except block to specify different treatment of different error types.

try:
    api.update_status(duplicate_text)
except tweepy.TweepError as error:
    if error.api_code == 187:
        # Do something special
        print('duplicate message')
   else:
       raise error

Twitter is preventing you from posting the duplicate text, so the only way around that is to just wait.

[KshitijKarnawat]

Just change the contents of api.update_status and your program should work fine