How can to search column with case insensitive with findAndCount

Issue type:

[ x ] question [ ] bug report [ ] feature request [ ] documentation issue

Database system/driver:

[ ] cordova [ ] mongodb [ ] mssql [ ] mysql / mariadb [ ] oracle [ x ] postgres [ ] sqlite [ ] sqljs [ ] react-native [ ] expo

TypeORM version:

[ ‘x’ ] latest [ ] @next [ ] 0.x.x (or put your version here)

Steps to reproduce or a small repository showing the problem:

const [results, total] = await this.userRepository.findAndCount({
    where: {
        name: Like(`%${options.keywords}%`),
        status: Equal(options.status)
    },
    order: { id: "DESC" },
    take: options.limit,
    skip: options.skip,
})

How can to search the name column with case insensitive in findAndCount api. I saw another solution is use query builder like below , so how to achieve this in findAndCount. Thanks you so much.

const posts = await repository.createQueryBuilder()
     .where("LOWER(title) = LOWER(:title)", { title })
     .getMany();

[n1kalai]

this is what you need exactly

 const [result, total] = await this.findAndCount(
    {
  where: { title: Raw(alias => `LOWER(${alias}) Like '%${value}%'`) },

take: take,
  skip: skip
}

);
  return {
    data: result,
    count: total
  }

[wyqydsyq]

Just wondering, would it not be possible for TypeORM to support a pattern like this?

    const title = 'Foo'
    this.myRepository.find({
      where: {
        'LOWER(title)': Lower(title)
      },
    })

Where string properties that are not included in the model’s properties don’t get magically resolved to the associated model property column and are instead used literally in the query e.g.

SELECT * FROM `myModel` WHERE LOWER(title) = LOWER('Foo')

This requires the developer to ensure it matches up to actual database columns without any type safety against the model’s defined properties, but it’s still a nicer API than constructing queries manually with QueryBuilder where you don’t get any type safety on column names anyway.