Dealing with ES6 export

/* foobar.js */

// ES6 export
const foobar = {
  foo: 'bar'
}
export default foobar;

// is equivalent to
module.exports = {
  default: foobar
}

/* foobar-log.js */

console.log(foobar);

So if I import foobar-log.js with imports-loader

import 'imports?foobar=./foobar!./foobar-log'

It gives object with default. It seems there’re no way toget just { foo: bar }.

[getsnoopy]

@SpaceK33z , #35 allows something like imports?foobar.default=foobar which would result in foobar.default = require('foobar'), but what we want in this case is something like imports?foobar=foobar.default to result in var foobar = require('foobar').default, since the ES6 transpilation will end up nesting the default export of the module under the default property of foobar’s exported object.

I tried to do something like that with v0.7.0 without luck. That makes sense though, considering . is an allowed character in file names, so there’s no way to know whether it’s part of the filename or property notation.

Having an easy way to import default exports and/or named exports would be nice.

[wildcard]

@getsnoopy try this e.g. imports-loader?{default:Auth0Lock}=auth0-lock!angular-lock using a ES2015 destructor will solve the problem