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Bug with passing custom separator while flattening nested object

See original GitHub issue

JsonFlattener.java:264 return new JsonFlattener(val.toString()).withFlattenMode(flattenMode).flattenAsMap(); is actually missing ‘.withSeparator(this.separator)’, and currently flattens nested object with default dot separator.

Mb there is similar issue for print mode, also for unflattener

Issue Analytics

State:
Created 7 years ago
Comments:5 (3 by maintainers)

Top GitHub Comments

1reaction

wnamelesscommented, Oct 13, 2016

The issue has been fixed in version 0.2.3. Sorry for the late fix.

0reactions

glebstscommented, Aug 12, 2016

But this instance is created in JsonFlattener itself, which is supposed to be working dependency library 😃 I think we do not understand each other. I made a test which is a copy of existing separator test, but with existing test5.json payload. Do you see the difference in flattening ‘i’?

  @Test
  public void testWithSeparatorAndNestedObject() throws IOException {
    URL url = Resources.getResource("test5.json");
    String json = Resources.toString(url, Charsets.UTF_8);
    assertEquals(
        "{\"a_b\":1,\"a_c\":null,\"a_d\":[false,{\"i_j\":[false,true]}],\"e\":\"f\",\"g\":2.3,\"z\":{}}",
        new JsonFlattener(json).withFlattenMode(FlattenMode.KEEP_ARRAYS)
            .withSeparator('_')
            .flatten());
  }

org.junit.ComparisonFailure: 
Expected :{"a_b":1,"a_c":null,"a_d":[false,{"i_j":[false,true]}],"e":"f","g":2.3,"z":{}}
Actual   :{"a_b":1,"a_c":null,"a_d":[false,{"i.j":[false,true]}],"e":"f","g":2.3,"z":{}}

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