Sequential Q.all()

From the docs

“You can turn an array of promises into a promise for the whole, fulfilled array using Q.all”

“If you have a number of promise-producing functions that need to be run sequentially, you can […] use the ultra-compact version. return funcs.reduce(Q.when, Q(initialVal));”

Problems

• The first approach returns a promise which eventually resolves to an array of values but it’s not guaranteed to be sequential.
• The second approach is guaranteed to be sequential but returns a promise that eventually resolves to only one of the async calculated values.

Request

Provide a means of Q.all() which is guaranteed to execute sequentially

Please if I’m missing anything and you can do this already somehow, let me know! Thanks 😃

[timjacobi]

If I understand correctly

You do! 😉

Does this make sense?

Yes, thanks for the code! It makes perfectly sense but it’s really really verbose. That’s why I’m asking for an additional method on Q like Q.all() but sequential. Q.sequentiAll() (pun intended)…

[Cdvalencia]

posible solution