"expression is not callable" with .andThen()

Hi there,

thanks for the amazing lib, love using every chance to make JS more Rusty and safe.

I did not manage to get a minimal repro yet, but I thought I’d post already in case someone has an idea.

This is the type signature of my Result-returning-function:

Unfortunately I get This expression is not callable. when calling .andThen() on it. Curiously enough .map() works.

Any ideas?

[incetarik]

I see, in short this error occurs when the overloads are not compatible with each other. I may try to fix this but that may cause changing the types and interfaces accordingly, yet I would try to minimize the visible changes to outside. I’ll do several things when I’m free but these days I’m busy, I’ll notify you about this when I start. @supermacro

[boredcity]

Honestly, I think I’m ready to throw in the towel at this point 😖 If I find a solution for it at some point in the future and the problem still persists I’d be happy to create a PR, but for now, it’s probably better to let someone with a better handle on Typescript have a go at this 😕